For a Binomial(n, p) distribution, which expression gives the mean?

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Multiple Choice

For a Binomial(n, p) distribution, which expression gives the mean?

Explanation:
The mean of a Binomial(n, p) is the expected number of successes in n independent trials with success probability p each. View the total successes as a sum of n independent Bernoulli(p) variables. By linearity of expectation, the expected value of that sum is the sum of the expectations, and a Bernoulli(p) variable has mean p. So the average number of successes is n·p, written as np. np(1-p) is the variance, not the mean. np^2 doesn’t represent the mean in general, and would only match np if p were 1. The number n is just the count of trials, not the average number of successes.

The mean of a Binomial(n, p) is the expected number of successes in n independent trials with success probability p each. View the total successes as a sum of n independent Bernoulli(p) variables. By linearity of expectation, the expected value of that sum is the sum of the expectations, and a Bernoulli(p) variable has mean p. So the average number of successes is n·p, written as np.

np(1-p) is the variance, not the mean. np^2 doesn’t represent the mean in general, and would only match np if p were 1. The number n is just the count of trials, not the average number of successes.

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